Basis as Subbase (topology)
1. Proposition
Let \((X, \mathcal{T})\) be a topological space and \(\mathcal{B}\) a basis. Then \(\mathcal{B}\) is a Subbasis for \(\mathcal{T}\)
2. Proof
TODO Let
Let \((X, \mathcal{T})\) be a topological space and \(\mathcal{B}\) a basis. Then \(\mathcal{B}\) is a Subbasis for \(\mathcal{T}\)
TODO Let
Date: nil
Created: 2024-10-11 Fr 22:24