additive functor induces functor on chain complexes

1. Proposition

Let \(\mathcal{A}, \mathcal{B}\) be abelian categories and \(\mathrm{Ch_*}(\mathcal{A}), \mathrm{Ch_*}(\mathcal{B})\) be the categories of chain complexes Suppose \(\mathcal{F}: \mathcal{A} \rightarrow \mathcal{B}\) is an additive functor, then \(\mathcal{F}\) induces a functor

\begin{align*} \mathcal{F}^*: \mathrm{Ch_*}(\mathcal{A}) \rightarrow \mathrm{Ch_*}(\mathcal{B}) \end{align*}

2. Proof

Date: nil

Author: Anton Zakrewski

Created: 2024-10-14 Mo 09:06