right exact functor as additive functor

1. Proposition

Let \(\mathcal{A}, \mathcal{B}\) be additive categories and \(\mathcal{F}: \mathcal{A} \rightarrow \mathcal{B}\) be a right exact functor Then \(\mathcal{F}\) is an additive functor

2. Proof

Date: nil

Author: Anton Zakrewski

Created: 2024-10-14 Mo 09:11