union of a chain of groups as group

1. Proposition

Let $G1 \subseteq G2 \subseteq G3 … $ be a chain of groups. Then \(G \coloneqq \bigcup_{n \in \mathbb{N}} G_n\) is also a group

2. Proof

2.2. inverse element

Let \(g_1 \in G\), then by assumption there exists a \(G_i\) such that \(g_1 \in G_i\) and hence \(g_1^{-1} \in G_i \subseteq G\)

Date: nil

Author: Anton Zakrewski

Created: 2024-10-11 Fr 22:28