category RMod as complete category
1. Proposition
Let \(R\) be a ring and \(\mathrm{RMod}\) the category RMod. Then \(\mathrm{RMod}\) is complete
Let \(R\) be a ring and \(\mathrm{RMod}\) the category RMod. Then \(\mathrm{RMod}\) is complete
Date: nil
Created: 2024-10-20 So 08:59