tensor functor as left adjoint
1. Proposition
Let \(R\) be a ring, \(M\) an \(R\)-module and \(\mathrm{RMod}\) the category RMod. Then the tensor functor
\begin{align*} (M \otimes_{R} -): \mathrm{RMod} \rightarrow \mathrm{Ab} \end{align*}is a left adjoint
2. Proof
Consider for arbitrary \(N,L \in \mathrm{Ob}(\mathrm{RMod})\) the maps
\begin{align*} \varphi: \mathrm{Hom}_{\mathrm{RMod}}((M \otimes_R N), L) \rightarrow& \mathrm{Hom}_{\mathrm{RMod}}(M, \mathrm{Hom}_{\mathrm{RMod}}(N,L)) \\ (f: M \otimes_R N \rightarrow L) \mapsto& (f': m \mapsto (n \mapsto f(m,n)) \\ \varphi^{-1}: \mathrm{Hom}_{\mathrm{RMod}}(M, \mathrm{Hom}_{\mathrm{RMod}}(N,L)) \rightarrow& \mathrm{Hom}_{\mathrm{RMod}}((M \otimes_R N), L) \\ (g: M \rightarrow (h: N \rightarrow L)) \mapsto& g': (m,n) \mapsto (g(m))(n) \end{align*}see:
2.1. bijectivity
2.2. naturality
todo:
- non commutative