exact sequence of k0 and k1
Proposition
Let be a ring, an ideal
Then there exists an exact sequence
natural in ideal pairs of rings
where
- is the relative K1-Group
- is K1 of a ring,
Proof
exact sequence with
exact at , exact at
exact at
a)
Suppose there exist a preimage .
Then
defines an isomorphism.
Thus or
b)
Let .
Then by equality in a grothendieck group
or after replacing with we get an isomorphism
then by some computation we may find a preimage of (omitted)
applying snake lemma
We have exact rows
Note that is a normal subgroup
thus we may apply the snake lemma for groups and normal subgroups for
and get an exact sequence
and an induced morphism
Now consider the exact rows
where we may apply the cokernel to
first vertically and get
and then horizontally to
or first horizontally
and then vertically to
This gives us the isomorphism since colimits commute with colimits
naturality
follows from functorality of & some natural transformation (omitted)